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Watt, unit of power in the International System of Units (SI) equal to one joule of work performed per second, or to 1/746 horsepower. An equivalent is the power dissipated in an electrical conductor carrying one ampere current between points at one volt potential difference.

## What is the total current in the circuit?

The total current in a series circuit is the same as the current through any resistance of the circuit. This total circuit current would remain the same through all the individual circuit resistors. Before any current will flow through a resistance, a potential difference, or voltage, must be available.

## What is the formula for total current in a series circuit?

Amperage (or Amps) in a Series Circuit The equation ​V = I/R​, known as Ohm’s Law, also holds true at each resistor in the circuit. The current flow throughout a series circuit is constant, which means it’s the same at each resistor. You can calculate the voltage drop at each resistor using Ohms’ Law.

## How do you calculate power in parallel?

Power can also be calculated using either P = IV or P=V2R P = V 2 R , where V is the voltage drop across the resistor (not the full voltage of the source). The same values will be obtained.

## How is voltage same in parallel?

A Parallel circuit has certain characteristics and basic rules: A parallel circuit has two or more paths for current to flow through. Voltage is the same across each component of the parallel circuit. The sum of the currents through each path is equal to the total current that flows from the source.

## How do you add 2 volts together?

If your signal source can source and sink current, you can connect a resistor to each output and use the voltage at a junction of the two. This will give an average of the two voltages. To get the sum, use an op-amp with a gain of +2.

## Why do voltages add in series?

When you add two batteries in series the potentials (voltage) are added because since the same charge is moved twice each time thru the same voltage (potential) the total work done is 2 * V but the current flow remains the same.