we simplify above circuit to calculate equivalent resistance, as one can see in digaram: RAB​=2+1+5=8Ω.

## How do I find equivalent resistance?

The voltage drop is the same across each parallel branch. The sum of the current in each individual branch is equal to the current outside the branches. The equivalent or overall resistance of the collection of resistors is given by the equation 1/Req = 1/R1 + 1/R2 + 1/R3 …

## What is the equivalent resistance across AB?

Equivalent resistance between A and B is RAB=2∣∣2=2/2=1Ω

## For what value of r the net resistance of the circuit will be 18 ohms?

R=16Ω. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

## Which combination reduces resistance in a circuit?

Parallel resistors

## In which sequence the resistance should be connected to get maximum equivalent resistance?

Answer. Answer: for finding maximum resistance we always connect the resistors in series. hence the answer is 8 ohm.

## How do you connect two resistance to a cell to get maximum current?

To get maximum current in a resistance of 3Ω, one can use m rows of n cells (connected in series) connected in parallel. If the total number of cells is 24 and the internal resistance of the cells is 0.5Ω then. (A). m=12,n=2.

## How do you connect two resistance to a cell to get a maximum current b minimum current?

To get minimum current, the two resistors should be connected in series. B)To calculate strength of total current in each case: 1) To get minimum current, the two resistors should be connected in series. 2) To get maximum current, we should connect the resistance in parallel.

## Which combination of a 2 Ω resistor and 4 Ω resistor offers the least resistance to current in the circuit?

Answer. Answer: parallel combination. hence, least resistance is offered in parallel resistance.

## When a resistance of 2 ohm is connected across the terminals of a cell?

When a resistance of 2 ohm is connected across terminals of a cell, the current is 0.5A. When the resistance is increased to 5 ohm, the current is 0.25A The e.m.f. of the cell is. Step by step solution by experts to help you in doubt clearance & scoring excellent marks in exams.

## When a resistance of 2 ohm is connected across the terminals of a cell the current is 0.5 A when the resistance is increased to 5 ohm the current is 0.25 A The EMF of the cell is?

Answer. When a resistance of 2Ω is connected across the terminals of a cell, the current is 0.5 A. When resistance is increased to 5Ω, the current is 0.25 A.

## When resistance of 2 ohm is connected across the terminal of the cell is the current across the cell is 5 ohm the current is 0.25 the emf of the cell?

When a resistance of 2ohm is connected across the terminals of a cell the current is 0.5amperes but when the resistance across the cell is 5 ohm and the current 0.25 the emf of a cell is: 1.5V.

## When a resistance R1 is connected across the terminals of a cell?

When a resistance R1 is connected across the terminals of a cell, the current is I1. When the resistance is changed to R2 , the current is I2 .

## When two ends of a metallic wire is connected across the terminals of a cell?

When two ends of a metallic wire are connected across the terminal of a cell some potential difference is set up between its ends.

## When the resistance of 9 Ohm is connected at the ends of a battery?

When the resistance of 9Ω is connected at the ends of a battery, its potential difference decreases from 40 volt to 30 volt .

## What is the terminal potential difference of a cell when short circuited?

(d) When cell is Short-circuited In short circuit so I = E R + r = E r and V = I R = 0 In short circuit current from cell is maximum and terminal potential difference is zero.

## What is a terminal of a cell?

A terminal is the point at which a conductor from a component, device or network comes to an end. All electrochemical cells have two terminals, referred to as the anode and cathode or positive (+) and negative (-).

## What is difference between cell potential and cell EMF which is larger among them?

The EMF is the maximum voltage that the battery can deliver whereas the magnitude of the potential difference is always less than the maximum possible value of emf. The emf force gains the electrical energy in the circuit whereas the potential difference loss the electrical energy in the circuit.